source: https://leetcode.com/problems/summary-ranges/description/
Snapshot Array
Table of Contents
Description
Implement a SnapshotArray that supports the following interface:
- SnapshotArray(int length) initializes an array-like data structure with the given length. Initially, each element equals 0.
- void set(index, val) sets the element at the given index to be equal to val.
- int snap() takes a snapshot of the array and returns the snap_id: the total number of times we called snap() minus 1.
- int get(index, snap_id) returns the value at the given index, at the time we took the snapshot with the given snap_id
Example 1:
Input: [“SnapshotArray”,”set”,”snap”,”set”,”get”]
[[3],[0,5],[],[0,6],[0,0]]
Output: [null,null,0,null,5]
Explanation:
SnapshotArray snapshotArr = new SnapshotArray(3); // set the length to be 3
snapshotArr.set(0,5); // Set array[0] = 5
snapshotArr.snap(); // Take a snapshot, return snap_id = 0
snapshotArr.set(0,6);
snapshotArr.get(0,0); // Get the value of array[0] with snap_id = 0, return 5
Constraints:
- 1 <= length <= 5 * 104
- 0 <= index < length
- 0 <= val <= 109
- 0 <= snap_id < (the total number of times we call snap())
- At most 5 * 104 calls will be made to set, snap, and get.
Solution
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/** * Your SnapshotArray object will be instantiated and called as such: * SnapshotArray obj = new SnapshotArray(length); * obj.set(index,val); * int param_2 = obj.snap(); * int param_3 = obj.get(index,snap_id); */ class SnapshotArray { private List<TreeMap<Integer, Integer>> snapshotList; private int nextSnapId = 0; public SnapshotArray(int length) { this.snapshotList = new ArrayList<>(); for(int i=0;i<length;i++){ this.snapshotList.add(new TreeMap<>()); this.snapshotList.get(i).put(0, 0); } } public void set(int index, int val) { this.snapshotList.get(index).put(nextSnapId, val); } public int snap() { return this.nextSnapId++; } public int get(int index, int snap_id) { return this.snapshotList.get(index).floorEntry(snap_id).getValue(); } } |